kang chuen tat


{ City } penang
< Country > malaysia
* Profession * biochemical engineer
User No # 116977
Total Questions Posted # 219
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Answers / { kang chuen tat }

Question { 1077 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 7 : In a shift-code, the letters of the alphabet are replaced by the numbers 1 to 26 starting at some letters. An example is : A = 25, B = 26, C = 1, D = 2, E = 3, F = 4, G = 5, H = 6, I = 7, J = 8, K = 9, L = 10, M = 11, N = 12, O = 13, P = 14, Q = 15, R = 16, S = 17, T = 18, U = 19,V = 20, W = 21, X = 22, Y = 23, Z = 24. In a different shift-code, the sum of the numbers representing the letters P and Q is 21. What word is represented by 13 10 21 23 25?


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 7 : S P A C E. P + Q = P + (P + 1) = 21, P = 10. Then 13 = S, 10 = P, 21 = A, 23 = C, 25 = E.

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Question { 1029 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 8 : In a shift-code, the letters of the alphabet are replaced by the numbers 1 to 26 starting at some letters. An example is : A = 25, B = 26, C = 1, D = 2, E = 3, F = 4, G = 5, H = 6, I = 7, J = 8, K = 9, L = 10, M = 11, N = 12, O = 13, P = 14, Q = 15, R = 16, S = 17, T = 18, U = 19,V = 20, W = 21, X = 22, Y = 23, Z = 24. In another shift-code, the sum of the numbers representing A, B and C is 42. What is the sum of the numbers which represent the letters of the word MARS using this code?


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 8 : 47. A + B + C = A + (A + 1) + (A + 2) = 42, A = 13. Then M = 25, A = 13, R = 4, S = 5. M + A + R + S = 25 + 13 + 4 + 5 = 47.

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Question { 1106 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 9 : In a shift-code, the letters of the alphabet are replaced by the numbers 1 to 26 starting at some letters. An example is : A = 25, B = 26, C = 1, D = 2, E = 3, F = 4, G = 5, H = 6, I = 7, J = 8, K = 9, L = 10, M = 11, N = 12, O = 13, P = 14, Q = 15, R = 16, S = 17, T = 18, U = 19,V = 20, W = 21, X = 22, Y = 23, Z = 24. There are two shift-codes in which the sum of the numbers representing the letters of the word HOLE is 48. What is the sum of the numbers representing the letters of the word BLACK in each of these codes?


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 9 : 39, 78. By first trial calculation, H + O + L + E = 10 + 17 + 14 + 7 = 48, B + L + A + C + K = 4 + 14 + 3 + 5 + 13 = 39. By second trial calculation, H + O + L + E = 23 + 4 + 1 + 20 = 48, B + L + A + C + K = 17 + 1 + 16 + 18 + 26 = 78.

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Question { 1109 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 10 : 6x – 2 – (4x – 7) equals – (A) 2x + 5, (B) 2x - 7, (C) 10x + 5, (D) - 2x + 5, (E) 2x – 9.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 10 : A, where 6x – 2 – (4x – 7) = 6x – 4x – 2 + 7 = 2x + 5.

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Question { 1066 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 11 : The value of (3^5) (3^3) / (3^2) is - (A) 3^6, (B) 3^9, (C) 3^4, (D) 3^(15/2), (E) 3^13.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 11 : A, where (3^5) (3^3) / (3^2) = 3 ^ (5 + 3 – 2) = 3^6.

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Question { 1054 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 12 : A tap drips at a rate of one drop of water every second. If it takes 600 such drops to fill a 100 millilitre bottle, the number of litres of water that would be wasted in 300 days is - (A) 432, (B) 4320, (C) 43200, (D) 432000, (E) 4320000.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 12 : B. Number of drops in 300 days = 300 day x 24 hour / day x 60 min / hour x 60 s / min x 1 drop / s = 2.592 x 10^7 drops. Number of litres of water = (2.592 x 10^7) drop / (600 drop) x 100 mL x 1 L / (1000 mL) = 4320 L.

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Question { 1079 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 13 : In an attempt to copy down a sequence of 6 positive integers in arithmetic progression, Adam wrote down the 5 numbers : 11, 25, 32, 37, 46. After checking with the original sequence, he found that not only did he miss one of the numbers entirely, he miscopied one of the others. Which of the above was not in the original sequence? (A) 11, (B) 25, (C) 32, (D) 37, (E) 46.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 13 : D. Difference d = 7. Actual arithmetic sequence : 11, 18, 25, 32, 39, 46 but 37 is out.

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Question { 7595 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 14 : The vertices of a cube are labelled from 1 to 8, in such a way that the sets of numbers corresponding to the vertices of the 6 faces are {1, 2, 6, 7}, {1, 4, 6, 8}, {1, 2, 5, 8}, {2, 3, 5, 7}, {3, 4, 6, 7} and {3, 4, 5, 8}. The vertex labelled 6 is furthest from the vertex labelled - (A) 1, (B) 3, (C) 4, (D) 5, (E) 7.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 14 : D. The top surface of a cube has the vertices with numbers 6, 7, 3, 4 which is corresponding to the vertices with numbers 1, 2, 5, 8 at the bottom surface. If it is 1 unit of length for lines of 6 – 7, 6 – 4 and 6 – 1, then it is 2^(0.5) unit for lines of 6 – 2 and 6 – 8, with the longest line 6 – 5 of length 3^(0.5).

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Question { 1142 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 15 : A motel cleaner has 8 master keys at home to open all the rooms in a large motel. Each room can be opened by just 1 of these keys. If 40 % of the rooms are left unlocked, what is the probability that the cleaner can get into a specific room if he selects 3 keys at random before leaving home to go to work? (A) 5 / 8, (B) 5 / 16, (C) 31 / 40, (D) 3 / 20, (E) 19 / 40.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 15 : A. Probability = 4 / 10 + (6 / 10) (3 / 8) = 5 / 8

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Question { 8247 }

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – QUESTION 16 : A committee of 6 people is to be chosen from 8 students and 6 teachers so that it contains at least 3 students and at least 2 teachers. The number of ways this can be done is – (A) 1050, (B) 1120, (C) 7560, (D) 840, (E) 2170.


Answer

VOLUNTEER TRAINING FOR DISADVANTAGED IN MATHS – ANSWER 16 : E. Two combinations are possible, either (3 students + 3 teachers) or (4 students + 2 teachers). Number of ways = 8C3 x 6C3 + 8C4 x 6C2 = (8!) / [ (3!) (5!) ] x (6!) / [ (3!) (3!) ] + (8!) / [ (4!) (4!) ] x (6!) / [ (4!) (2!) ] = 2170. Excel language is =fact(8)/(fact(3)*fact(5))*fact(6)/(fact(3)*fact(3))+fact(8)/(fact(4)*fact(4))*fact(6)/(fact(4)*fact(2)), which is also equal to 2170.

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