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If the bandwidth of the channel is 8 Kbps, How long does it
take to send a frame of 200,000 bits out of this device?
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Answer / joyjit bhattacharje
200,000 bits=200,000/1024 Kb=195.3125 Kb
Given,
8 Kb =1 s
1 Kb =1/8 s
195.3125 Kb =1*195.3125/8 s
=24.414 s
| Is This Answer Correct ? | 26 Yes | 4 No |
Answer / farzan khan
Given:
frame size= 200000 bits
bandwidth= 8 kbps
Solution:
1kb= 1024 bits
8kb= 8 x 1024= 8192 bits
So,
formula: time= frame size/bandwidth speed
time taken= 200000 bits/ 8192 bits/seconds ==> 24.414 seconds (Answer)
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| Is This Answer Correct ? | 7 Yes | 5 No |
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