Which is the Best institute to do academic Project in Java?
Need information about institutes at Ameerpet, Hyderabad.
Answers were Sorted based on User's Feedback
Answer / amarnathreddy
Naresh i Technologies,
Ameerpet.
This is the best institute to learn JAVA,J2EE.
Mr.Verma is the best for STRUTS,SPRING and HIBERNATE in Naresh Technologies.
Don't miss his classes.He is the best faculty
| Is This Answer Correct ? | 63 Yes | 6 No |
Answer / vishal gupta
netmax technologies chandigarh is best institute of java
| Is This Answer Correct ? | 0 Yes | 19 No |
I think every institute is same. Same concepts, same
strength of students. But one thing is very important
listening classes carefully is not only learning java and do
practice in lab and think logically when writing programs
and learn what exactly the flow of execution of programs.
regards.
Giridhar Gangapatnam
| Is This Answer Correct ? | 6 Yes | 27 No |
Answer / ashwin
Inetsolv is the best instititue for learning java/j2ee
| Is This Answer Correct ? | 4 Yes | 29 No |
Answer / venki
Inet solve is the best institute to learn java/j2ee
| Is This Answer Correct ? | 3 Yes | 29 No |
Answer / srikanth reddy
java learning center is best center for java training in
bangalore which is in mathikere srinivas sir is best
faculty in india
| Is This Answer Correct ? | 2 Yes | 28 No |
Answer / skumar
NeoApp Technologies, Advanced Project Training.
Where you will undergo all the process of the SDLC.They provide you the path how to do the things and they will guide you.Which inturn equal to the 3 years of exp in any it company
| Is This Answer Correct ? | 1 Yes | 28 No |
What is flatmap java?
Write a program for the problem: the array of inetegers indicating the marks of the students is given, U have to calculate the percentile of the students aaccording to this rule: the percentile of a student is the %of no of student having marks less then him. For eg: suppose Student Marks A 12 B 60 C 80 D 71 E 30 F 45 percentile of C = 5/5 *100 = 100 (out of 5 students 5 are having marks less then him) percentile of B = 3/5*100 = 60% (out of 5, 3 have markses less then him) percentile of A = 0/5*100 = 0%.
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