(1)In Cl Program,Are PGM and ENDPGM mandatery Keywords or not .If yes, please tell me why these keywords is necessary. (2)If we will not define these two keywords (PGMand ENDPGM) then any error will be come or not.
5 19488I have dataset DS1 which has records say 1 2 3 4 5 ... ... etc And also I have second dataset DS2 whcih has records 1 3 4 5 6 8 .. ... Both the files are sorted and now I want to compare these files and write it into the third files if the records are matching.
4 10244Write a code check the checkbox in the web table which is in the 4th row and fifth column (Use child item concept)
2 16945requirement is for combo box your expected value is str= "Denver.Frankfurt.London.Los Angeles.Paris.Portland.San Francisco.Seattle.Sydney.Zurich" you must get the text in combo box and need to compare them how
1475requirement is for combo box your expected value is str= "Denver.Frankfurt.London.Los Angeles.Paris.Portland.San Francisco.Seattle.Sydney.Zurich" ar = Window("Flight Reservation").WinComboBox("Fly From:").GetContent your actual value is : that shows data in combo box how can u test the both data is correct or not by using split function
1 3802I have DATE filed like DD-MM-YYYY, So I want output should be MM/DD/YYYY using JCL? Can anybody post the answer for above requirement?
4 18056HOw Hash Partion Works Thank you in Advance i have doubts on Hash Partion TEch Could please give me the clear understandable notation example e_id,dept_no 1,10 2,10 3,20 4,20 5,30 6,40 i have TWo Nodes/Three Nodes My questions are: 1).if i select hash key as e_id how Hash partion will distribute the data in to two NOdes/three NOdes 2).if i select hash key as dept_no how Hash partion will distribute the data in to two NOdes/three NOdes sivakumar.katta7@gmail.com
5 9052Post New FIS Interview Questions
Hai Experts can any one send me some finance interview questions ,my mail id is c.sujatha2008@gmail.com,please send quickly it's so need.
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why would you like to change your career from IT?
You have designed test cases to provide 100% statement and 100% decision coverage for the following fragment of code. If width > length then biggest_dimension = width else biggest_dimension = length end_if the following has been added to the bottom of the code fragment above. Print 'biggest dimension is ' &biggest_dimensionprint 'width: ' & width print 'length: ' & length how many more test cases are required?
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