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void main()
{
int i=5;
printf("%d",i+++++i);
}
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Answer Posted / sheetal
gives error
"error C2105: '++' needs l-value"
because it parses above expression in "((i++)++)+i), so in
2nd unary operator it searches for l-value.
If we modify above pgm into following way:-
void main()
{
int i=5;
printf("%d",((i++)+(++i)));
}
it will give answer 12.
because once last pre-unary increment operator is operated,
i is incremented to 6 and 6+6 = 12.
if we put one more print for i's value, it will give i =7.
because first post-increment operator is operated after
first printf statement as follows.
void main()
{
int i=5;
printf("%d",((i++)+(++i)));
printf("%d\n",i); // ===> i =7
}
| Is This Answer Correct ? | 4 Yes | 1 No |
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