Answer Posted / sri k. hari

/* Author : Sri K. Hari
Description : program for series
1*3*5-2*4*6+3*5*7-4*6*8...........upto n terms
*/

#include<stdio.h>
#include<conio.h>

void main()
{
int n,i,res,finres;
char opt ;
clrscr () ;
do
{
res = 0 ;
finres = 0 ;
printf ( " \n Enter the last number " ) ;
scanf("%d",&n);

for ( i = 1 ; i <= n ;i++ )
{
res = ( i * (i+2) * (i+4) ) ;

if ( (i%2) == 0 )
finres = finres - res ;
else
finres = finres + res ;
}
printf ( " \n the result is : %d ", finres) ;
printf ( "Do you want to continue (Y/N)" ) ;
scanf ( "%s",&opt) ;
}while ( (opt == 'y' ) || (opt == 'Y' ) ) ;
}

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