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TISL PLACEMENT PAPERS -------------- Placement Paper 10
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TATA -IBM
-----------
LETTER SERIES
answers
- -------
1)e e f g g h i i --- j
2)a z a y b z b y c --- a e x y z z
3)d e f d e f g h i --- d e f g h g
4)c d e x y z f g h x y z i j k l m i
5)de f de g d e --- d j z h i h
6)a b c z a b c y a b c --- a b x y z x
7)d g b h i b j k b ---- b e l m n l
8)t s p t s q t s --- r s t v w r
9)q a r b s a t a r b ---- a b e r s s
10)b c c d e e f g -- e f g h i g
11)e f h i k l --- m n o p q n
12)a b cc d e ff g -- efghi h
13)a m n b op c --- depqr q
14)ttt sss qqq p --- opqrs p
15)ddffhhjj--- ijklm l
16)mnmnklopopkl ----- kopqr q
17)cddeeefff--- efghi f
18)gfde---- bcfgh c
19)dfhjl ----- jklmn n
20)abcijdefij---- ghijk g
21)efgefghefghi ---- e
22)bcbdedffghi ---- fghjk h
23)aababccdc --- cdefg d
24)aibcidef --- efghi i
25)cehl --- opqrs q
26)abdehimn --- pqrst s
27)becfdge --- efghi h
28)agbhc ---- dfghi i
29)adhko --- pqrst r
30)efghjklno --- pqrst q
31)aeibf --- cdgij j
32)aedhg-- hijkl k
33)zdwgt --- hijkl j
34)zeiyijxj--- ijklm k
35)dqreuvg--- vwxyz y
36)ksjtiuh--- vwxyz v
37)rsjtuhvw--- cdefg f
38)ieajfbk ---- cdefg g
39)hebijej ---- ghijk g
40)njfmiel --- dhijm h
TISL Placement Papers | TISL Interview Procedure | TISL
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Interview Questions
1)
main()
{
char *p1="name";
char *p2;
p2=(char*)malloc(20);
while(*p2++ = *p1++);
printf("%s\n",p2);
}
Ans:empty string.
2)
main()
{
int x=20,y=35;
x=y++ + x++;
y= ++y + ++x;
printf("%d%d\n",x,y);
}
Ans : 57 ,94
3)
main()
{
int x=5;
printf("%d%d%d\n",x,x<<2,x>>2);
}
ans: 5,20,16
4)
#define swap(a,b) a=a+b;b=a-b;a=a-b;
main()
{
int x=5;y=10;
swap1(x,y);
printf("%d %d\n",x,y);
swap2(x,y);
printf("%d %d\n",x,y);
}
int swap2(int a, int b)
{
int temp;
temp=a;
b=a;
a=temp;
return;
}
like that
ans: 10 ,5
10 ,5
5)
main()
{
char *ptr = " Ramco Systems"
(*ptr)++;
printf("%s\n",ptr);
ptr++;
printf("%s\n",ptr);
}
Ans: Samco Systems
amco systems
6)
main()
{
char s1[]="Ramco";
char s2[]= "systems";
printf("%s",s1);
}
Ans: compilation error giving that it can not
modified Lvalue.
7)
main()
{
char *p1;
char *p2;
p1=(char *)malloc(25);
p2=(char *)malloc(25);
strcpy(p1,"Ramco");
strcpy(p2,"systems");
strcat(p1,p2);
printf("%s",p1);
}
Ans: Ramcosystems
TISL Placement Papers | TISL Interview Procedure | TISL
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Interview Questions
8)
The following variable is available in file1.c
static int average float;
Ans: all the functions in the file1.c can access
the variable.
9)
Ans : [2] . extern int x;
check the answer.
10) Another problem with
#define TRUE 0
somecode.
while(TRUE)
{
somecode
}
This will not go into the loop as TRUE is defined
as 0.
Ans : None of the above i.e (D).
11)
Ans :
[4]. A question in structures where the
members are dd,mm,yy.
mm:dd:yy
09:07:97
15) structure kswap
Ramco India
Ramco Systems Corporation
Ramco .... Limited.
After swaping the result will be
First two will be swaped
Ramco Systems Corporation.
Ramco India
Ramco .... Limited.
16) int x;
main()
{ int x=10;
x++;
change-value(x);
x++;
modify-value();
printf("First output:%d\n",x);
x++;
change-value(x);
printf("secpnd output:%d\n",x);
modify-value();
printf("Third output:%d\n",x);
}
modify-value()
{
return(x+=10);
}
change-value()
{
return(x+=1);
}
Ans: 12 , 1 , 1
17) main()
{
int x=10;y=15;
x = x++;
y = ++y;
printf("%d %d\n",x,y);
}
Ans: 11, 16
18)
main()
{
int a=0;
if(a==0) printf("Ramco Systems\n");
printf("Ramco Systems\n");
}
Ans: only one time "Ramco Systems" will be printed.
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my question is : reverse a string in COBOL program (please write a code asap) input file: 1234abcdef output file: 8765_____ abc*$#1___ 1_2_3_4__ cdef____ghi h_k_z_a__ a_z_k_h___ ihg____ghi 4_3_2_1___ 1#$*cba__ ______5678 fedcb4321
