Answer Posted / Shobhit Gupta
The sequence you provided appears to be the Fibonacci sequence where each number is the sum of the two preceding ones, with the exception that the first two numbers are 1 and 2. To find the 40th term, we can use Binet's formula: F(n) = (Phi^(n - 1) - (-phi)^(n - 1)) / sqrt(5). Phi is the golden ratio (approximately 1.61803), and phi is its multiplicative inverse (approximately -0.61803). By calculating F(40) using this formula, we find that the 40th term of your sequence is approximately 10,952.nnNote: Due to rounding errors, the calculated result may not perfectly match the actual Fibonacci number. However, it should be close.
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