A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is
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Answer Posted / Shilpi Garg
To solve this problem, let's assume the car's speed is C and the train's speed is T (T being 50% faster than C). Since they both reach point B at the same time and the train lost 12.5 minutes due to stops, their travel times are equal:
Time_C + (Time_T * 0.2) = Distance / Speed_C = 75 km / C
Solving for C:
C^2 = (75 km * C) / (1 - 0.2)
C = sqrt((75 km * C) / (1 - 0.2))
C^2 = 375 km / 0.8
C = sqrt(468.75 km²)
Approximate speed of the car: C = 21.7 m/s or about 78.6 km/h
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