Here, in first case, i=5, j=(i++)+ (i++) + (i++)............ i is added thr

1)
int i=5;
j=i++ + i++ + i++;
printf("%d",j);This code gives the answer 15.But if we
replace the value of the j then anser is different?why?

2)int i=5;
printf("%d",i++ + i++ + i++);
this givs 18.

Question Posted / keerthan

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Answer Posted / keerthan

Here, in first case, i=5, j=(i++)+ (i++) + (i++)............ i is added three times without incrementing because it is post incremented so... 5 is added with 5 and again with 5 answer is 15.
where as in second case... execution from right to left when it is done... initially i=5, first i++ this value is 5 then incremented so that 6 is added to 5... now is incremented again so 7 now 7+6+5 =18.

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