if the voltage across the lamp drops by 1%, the power drawn
will be reduced by how many %?
- 5 Answers
- 22506 Views
- PSPCL, I also Faced
- E-Mail Answers
Answer Posted / nirmal maity
Let, voltage across the lamp =100v and resistance R =100 ohm
so, power P =v*I = 100*1=100W {I =V/R =100/100=1 }
If the voltage across the lamp drops by 1 percentage , then present voltage is 99v
Then present power drown by the lamp whose resistance R =100 ohm is P =V^2/R = 98*98/100 = 98.01W .
So power drop of the lamp is 100-98 =2 w
so the power drawn will be reduced by 2percentage
| Is This Answer Correct ? | 29 Yes | 9 No |
Post New Answer View All Answers
What are the advantages of skewing of cage rotor conductors?
WHICH SIZE A.B.CABLE IS USED FOR 11KV.
WHAT IS SHORT CIRCUIT STRENGTH OF 100 AMPS MCCB?
Earth has zero potential then what would be the neutral potential ?
grr resistance & contrator malt continuous
List some examples of renewable energy?
how we calculate the dick for a pole?
How can we design a HVAC Plant room which includes AHU,FCU,Chillers,Cooling towers, Pumps etc & how will they work? any Drawing if possible?
IN SINGLE PH TRANSFORMER IF LEKAGE IMPEDANCE DROP IS NEGLECTED ,THE FLUX IN THE MAGNETIC CORE and the lekage flux linking a winding are a)proportional to the applied v to the winding i respectively.
what does a k rating in a transformer means?
what is cathodic protaction?
What are the weight of 800KV DA,DB and DC type tower ?
In 90 kva alternator that produce the output voltage is 115(p-n),200(p-p) at 1500 rpms means what ampere it produced ?
Why air circuit breaker off due to power failure?
why we cannot protect 100% winding of an alternator by using differential protection?
