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Write a program to resize an array of 5 elements to 4 elements and display all the elements.

Answer Posted / jon doe

C style answer:

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
// create array with 5 elements
int *array5 = (int *) calloc(5, sizeof(int));
for(int i = 0; i < 5; ++i) {
array5[i] = rand();
}

// resize array
int *array4 = (int *) realloc(array5, 4 * sizeof(int));

for(int i = 0; i < 4; ++i) {
printf("%d) %d
", i, array4[i]);
}

free(array4);

return EXIT_SUCCESS;
}

C++ style answer:

int main(int argc, char *argv[]) {
// create array with 5 elements
int *array5 = new int[5]();
for(int i = 0; i < 5; ++i) {
array5[i] = rand();
}

// resize array
int *array4 = new int[4];
// copy array via loop. Alternative: use an array-copy function such as memcpy() for C or java.lang.System.arraycopy() for Java
for(int i = 0; i < 4; ++i) {
array4[i] = array5[i];
}
delete[] array5; // not used anymore

// print array
for(int i = 0; i < 4; ++i) {
printf("%d) %d
", i, array4[i]);
}

delete[] array4;

return EXIT_SUCCESS;
}

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