Ex:1 #define A 10+10 void main() { int a; a = A*A; cou

#define d 10+10
main()
{
printf("%d",d*d);
}

Question Posted / jyothikrishna

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Answer Posted / jyothikrishna

Ex:1
#define A 10+10
void main()
{
int a;
a = A*A;
cout<<a<<endl;
}

Ans : 120

Explanation:
When you compile this program. A*A will be converted into 10+10*10+10. Here it follows BODMAS rule first it will perform multiplication and next it will perform addition.

First 10+10*10+10 = 10 + 100 + 10
next 10 + 100 + 10 = 120 (Answer)

Ex:2
#define A (10+10)
void main()
{
int a;
a = A*A;
cout<<a<<endl;
}

Ans : 400

Explanation:
When you compile this program. A*A will be converted into (10+10)*(10+10). Here it follows BODMAS rule first it will perform Bracket values and next it will perform multiplication.

First (10+10)*(10+10) = 20 * 20
next 20 * 20 = 400 (Answer)

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