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How to find the count of letter "L" in HELLO

Answer Posted / ajit nayak

FUNCTION
---------
CREATE OR REPLACE FUNCTION FN_WORD_CNT (V_NAME VARCHAR2,V_SRCH_WRD VARCHAR2)
RETURN NUMBER
IS

I_COUNT NUMBER;
I_WRD_CNT NUMBER;

TYPE V_WORD IS TABLE OF VARCHAR2(10)
INDEX BY BINARY_INTEGER;
V_S_WORD V_WORD;

BEGIN
I_WRD_CNT := LENGTH(V_NAME);
DBMS_OUTPUT.PUT_LINE(I_WRD_CNT);
I_COUNT := 0;

FOR I IN 1..I_WRD_CNT
LOOP
SELECT SUBSTR(V_NAME,I,1)
INTO V_S_WORD(I)
FROM DUAL;

END LOOP;
FOR I IN 1..V_S_WORD.COUNT
LOOP

IF(V_S_WORD(I) = V_SRCH_WRD) THEN
I_COUNT := I_COUNT + 1;

END IF;
END LOOP;
RETURN I_COUNT;
END;

FOR RUN
-------

select FN_WORD_CNT('AJIT','A')
from dual;

PROCEDURE
---------
CREATE OR REPLACE FUNCTION FN_WORD_CNT (V_NAME VARCHAR2,V_SRCH_WRD VARCHAR2)
RETURN NUMBER
IS

I_COUNT NUMBER;
I_WRD_CNT NUMBER;

TYPE V_WORD IS TABLE OF VARCHAR2(10)
INDEX BY BINARY_INTEGER;
V_S_WORD V_WORD;

BEGIN
I_WRD_CNT := LENGTH(V_NAME);
DBMS_OUTPUT.PUT_LINE(I_WRD_CNT);
I_COUNT := 0;

FOR I IN 1..I_WRD_CNT
LOOP
SELECT SUBSTR(V_NAME,I,1)
INTO V_S_WORD(I)
FROM DUAL;

END LOOP;
FOR I IN 1..V_S_WORD.COUNT
LOOP

IF(V_S_WORD(I) = V_SRCH_WRD) THEN
I_COUNT := I_COUNT + 1;

END IF;
END LOOP;
RETURN I_COUNT;
END;

RUN THIS PROCEDURE
------------------
DECLARE
v_name varchar2(10) := '&name';
v_srch varchar(2) := '&str';
i_cnt number;
begin
DBMS_OUTPUT.PUT_LINE('ENTER NAME '||v_name||CHR(10)||' SEARCH STR '||v_srch);
P_FN_WORD_CNT(v_name,v_srch,i_cnt);
END;

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