Interested to Buy Any Domain ? << Click Here >> for more details...
Why does connect() succeed even before my server did an accept()?
- 1 Answers
- 2198 Views
- I also Faced
- E-Mail Answers
Answer Posted / chaitanya
Once you have done a listen() call on your socket, the kernel is primed to accept connections on it. The usual UNIX implementation of this works by immediately completing the SYN handshake for any incoming valid SYN segments (connection attempts), creating the socket for the new connection, and keeping this new socket on an internal queue ready for the accept() call. So the socket is fully open before the accept is done.
The other factor in this is the 'backlog' parameter for listen(); that defines how many of these completed connections can be queued at one time. If the specified number is exceeded, then new incoming connects are simply ignored (which causes them to be retried).
| Is This Answer Correct ? | 0 Yes | 0 No |
Post New Answer View All Answers
How do I convert a string into an internet address?
What is socket address with example?
Are unix sockets faster than tcp?
Are sockets files?
What is a sae socket?
Why do we need sockets?
How can I tell when a socket is closed on the other end?
What is a socket connection?
How is a socket created?
What is the difference between SO_REUSEADDR and SO_REUSEPORT?
What's the difference between impact sockets and regular sockets?
How can I write a multi-homed server?
What is sae socket?
What is difference between socket () and serversocket () class?
What does af mean in sockets?
