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What is the amount of cement,sand and course aggregate(jully)(in kgs) required for the RCC of an area of 450 square feet and 5 inch depth if the concrete mixing ratio is 1:2:4(cement:sand:jully)?your answer will be very helpful.
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Answer Posted / mohd zubairali
first converted into meters we get 5.311 cum the ratio is (1:2:4)
0.92*1440/4=331.2kg/cum
cement is 331.2*5.311= 1759 kg
1759/50 = 35.1=36 BAGS of cemnt
.46*5.311=2.443CUM of sand
.92*5.311= 4.886CUM of aggregate
NOTE:-ONE CUM OF concrete IS 0.46cum of sand.
ONE CUM OF CONCRETE IS 0.92 CUM OF AGGREGATE
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