Interested to Buy Any Domain ? << Click Here >> for more details...
solve this is my problem byte a=40,byte b=50 both add value is 90 this is with in range of byte... byte range is -128to 127....
why this pgm gives error like type mismatch....
package javapgms;
public class byte1 {
public static void main(String args[])
{
byte a=40,b=50;
byte c=a+b;
System.out.println(c);
}
}
note : dont use int k...
a,b,c are in byte range... mind it..
- 2 Answers
- 6146 Views
- I also Faced
- E-Mail Answers
Answer Posted / chaya k
There is a complile time error occurs while adding byte variables a and b together. Because we have to know that when we add byte numbers we get int as a resultant datatype.
Here,both a and b are in byte, then resultant datatype after addition is in int datatype but not in byte.We can't store value from int datatype to value in byte datatype so we do down-typecasting as:
byte c=(byte) a+b;
If you don't want to downcaste you should store resultant value in int datatype only as,
int c=a+b;
| Is This Answer Correct ? | 7 Yes | 1 No |
Post New Answer View All Answers
What is ascii code?
What is %02d?
How many bits is a 64 bit byte?
Explain the selection sort algorithm and state its time complexity?
When can an object reference be cast to an interface reference in java programming?
What does regex mean?
What is data member in java?
How many types of exception can occur in a java program?
Can we use catch statement for checked exceptions when there is no chance of raising exception in our code?
Can a constructor be protected?
What do you understand by casting in java language?
What is method with example?
Can there be an abstract method without an abstract class?
What is instance means in java?
What is java in simple terms?
