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Answer Posted / malik
#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
for(i=5;i>=0;i--)
{
for(j=1;j<=i;j++)
{
printf("%d", j);
}
printf("\n");
}
getch();
}
| Is This Answer Correct ? | 4 Yes | 0 No |
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