¦void main()
¦{
¦int i=10,j;
¦ j=i+++i+++i;
¦printf("%d",j);
¦getch();
¦}
¦ output:-30
but in same question if we write as-
¦void main()
¦{
¦int i=10;
¦ int j=i+++i+++i;
¦printf("%d",j);
¦getch();
¦}
¦ output:-33
why output is changed from 30 to 33. Can any body answer...
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Answer Posted / abhishek kumar
this question is itself is confusing question as if we
compile it with c,c++ compiler, the compiler itself get
confuse and it take i=10 all time as it does not make
distinguish between operator in expression(i+++i+++i) and
give output as 30, but if we compile it with java compiler
it output is 33, as java compiler make distinguish between
operator as (i++ +i+ ++i).
so my conclusion is that question given above is confusing
itself that why output are varying every time.
| Is This Answer Correct ? | 1 Yes | 3 No |
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