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#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k;
for(i=1;i<=5;i++)
{
for(j=1;j<=i;j++)
{
printf("%d ",(i+j+1)%2);
}
printf("\n");
}
getch();
}
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| Is This Answer Correct ? | 59 Yes | 11 No |
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