Answer Posted / satishraja

str ="bibhu@#$%&das&*)(SUndar"
L=len(str)
For i=1 to l
x=left((right(str,l-i+1)),1)
If ASC(ucase(x))>=65 and ASC(ucase(x))<=90 then
Print x
End If
Next

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1148

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2230

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975

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1822

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1393

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1009

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