A half wave rectifier is used to supply 50vdc to resistive
load of 800ohms the semiconductor diode has a forword
resistance of 25ohms,calculate ac voltage required?
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Answer Posted / dhafer faisal
Answer:
Output d.c. voltage, Vdc = 50 V
Diode resistance, rf = 25 Ω
Load resistance, RL = 800 Ω
Let Vm be the maximum value of a.c. voltage required.
∴ Vdc = Idc × RL
= π( )
× = ×
π +
m m
L L
f L
I V
R R
r R
   =   + 
∵ m
m
f L
V
I
r R
or 50 = 800
π (25 800)
×
+
Vm
∴ Vm = π 825 50
800
× × = 162 V
Hence a.c. voltage of maximum value 162 V is required.
| Is This Answer Correct ? | 15 Yes | 6 No |
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