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Answer Posted / arun
YES WE CAN IN FACT ON HIGHER FREQUENCY THE LOSSES WILL DECREASES AS Ph=Kh *f*Bmax1.6* (hystereis loss )
Pe=Ke*f2*Bmax2(eddy current loss)
V=4.44*f*Bmax*N
so if i put the value of Bmax from the third equetion then eddy curren loss will be independent of the frequency but hysterysis loss is inverly propotional to B(power .6 )
so from here its clear that if frequencuy increase then losses decreases so
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