what is the output of the below program & why ?
#include<stdio.h>
void main()
{
int a=10,b=20,c=30;
printf("%d",scanf("%d%d%d",&a,&b,&c));
}
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Answer Posted / gaurav sharma
because printf returns the number of printed arguments .here
3 arguments taken ,the concept is ( scanf also return the
number of arguments so 3 returned to printf .m gaurav
sharma ,,,,,works in aricent.
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