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Write a program that finds the minimum total number of
shelves, including the initial one required for this loading
process.
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Answer Posted / raveathul farzaana.m.y
#include<stdio.h>
#include<conio.h>
void main()
{
char packet[25];
int
n,counta=0,countb=0,countc=0,countd=0,counte=0,countf=0,countg=0,counth=0,counti=0,countj=0,countk=0,countl=0,countm=0,countn=0,counto=0,countp=0,countq=0,countr=0,counts=0,countt=0,countu=0,countv=0,countw=0,countx=0,county=0,countz=0;
int shelves=0;
printf("Enter the number of packets:");
scanf("%d",&n);
printf("Enter the packets one by one:");
for(i=0;i<n;i++)
{
scanf("%c",&packet[i]);
}
for(i=0;i<n;i++)
{
if(a[i]==A)
counta++;
if(a[i]==B)
countb++;
if(a[i]==C)
countc++;
if(a[i]==D)
countd++;
if(a[i]==E)
counte++;
else if(a[i]==F)
if(a[i]==G)
countg++;
countif(a[i]==H)
counth++;
if(a[i]==I)
counti++;
if(a[i]==J)
countj++;
if(a[i]==K)
countk++;
if(a[i]==L)
countl++;
if(a[i]==M)
countm++;
if(a[i]==N)
countn++;
if(a[i]==O)
counto++;
if(a[i]==P)
countp++;
if(a[i]==Q)
countq++;
if(a[i]==R)
countr++;
if(a[i]==S)
counts++;
if(a[i]==T)
countt++;
if(a[i]==U)
countu++;
if(a[i]==V)
countv++;
if(a[i]==W)
countw++;
if(a[i]==X)
countx++;
if(a[i]==Y)
county++;
if(a[i]==Z)
countz++;
}
if(n>0)
{
if(counta>0)
shelves++;
if(countb>0)
shelves++;
if(countc>0)
shelves++;
if(countd>0)
shelves++;
if(counte>0)
shelves++;
if(countf>0)
shelves++;
if(countg>0)
shelves++;
if(counth>0)
shelves++;
if(counti>0)
shelves++;
if(countj>0)
shelves++;
if(countk>0)
shelves++;
if(countl>0)
shelves++;
if(countm>0)
shelves++;
if(countn>0)
shelves++;
if(counto>0)
shelves++;
if(countp>0)
shelves++;
if(countq>0)
shelves++;
if(countr>0)
shelves++;
if(counts>0)
shelves++;
if(countt>0)
shelves++;
if(countu>0)
shelves++;
if(countv>0)
shelves++;
if(countw>0)
shelves++;
if(countx>0)
shelves++;
if(county>0)
shelves++;
if(countz>0)
shelves++;
printf(shelves)
}
else
{
printf("-1");
cont... after this
| Is This Answer Correct ? | 17 Yes | 3 No |
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