Answer Posted / avcs

The answer is 28m.
Let A completes race in t1 secs.
velocity(A)=100/t1 ; Velocity (B)=90/t1;

B completes race in t2 secs
Velocity(B)=100/t2; Velocity (C)=80/t2;

now 90/t1=100/t2 => t2=10*(t1)/9;

Velocity (C) = 80 * 9/10*(t1)= 72/t1;

So A defeats C by 28 meters.

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