11. static class A {
12. void process() throws Exception { throw new Exception();
}
13. }
14. static class B extends A {
15. void process() { System.out.println(”B”); }
16. }
17. public static void main(String[] args) {
18. new B().process();
19. }
What is the result?
1 B
2 The code runs with no output.
3 Compilation fails because of an error in
line 12.
4 Compilation fails because of an error in
line 15.
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Answer Posted / vasanth g
Here we are directly process method of class b.
so ans B that is 1st option....
consider this
static classA {
void process() throws Exception { throw new Exception(); }
}
static class B extends A {
void process() { System.out.println(�B �); }
}
public static void main(String[] args) {
A a=new B();
a.process();
}
in this program compilation fails at a.process
because compiler doen't know that reference a point on class
B where there's no exception. a is of A type and A's method
throws exception that isn't handled .a.process() enclosed in
try catch block.
| Is This Answer Correct ? | 4 Yes | 0 No |
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