why transformer ratings in kva?
Answer Posted / muzahir hussain
KVA is the unit of apparent power. Apparent power consists of active and reactive power.Active power is the share of the apparent power which transmit energy from source(generator) to user. Reactive is the share of the apparent power which represent a useless oscillation of energy from the source to the user and back again or it used to transfer the power inside the core. So we have to calculate both active and reactive power. therefore we calculate apparent power and the unit of apparent power is KVA.
In shortly we can say that the losses of transformer depends on voltage and current i.e cu loss depends on current(amp) and the iron loss depends on voltage(volts)and k is capacity. So rated in KVA not in KW because it does not depends on power factor.I hope that it is correct up to my knowledge only.
| Is This Answer Correct ? | 0 Yes | 0 No |
Post New Answer View All Answers
why capacitance effect is predominant in underground cable transmission and inductance effect is predominant in over head line transmission?
What is cut-off rate?
Can we use BS 6651 and BS EN 62305 standards for computer room lightning ptotection in substation?
Define open loop control system.
What does the term power factor shows?
what is the star delta connetion and how can do it a three phase motor with control witing with picture
Differentiate between kirchhoff’s first law and kirchhoff’s second law?
how do u gauge the size of the cable ?for eg. consider a 300 sqmm L.T Cable.How do u determine the size of the cable seeing it pratically?
advantage and disadvantage of team work?
How to use earthing on shipments.
Details about Flux Compensated magnetic Amplifer starter for motors
I have a situation to design sub-Distribution board/Panel meant for feeding power sockets. In the incomer CAN i Take TP MCCB with Neutral Link and All the outgoing feeders with to sockets with TP MCCB and Neutral Link? P.S : My System is IT Earthing
Help need in transformer !? Hello Friends The parameters of 2300/230 v 50hz t/f is R1=0.286 ohm R`2=0.319 ohm Rc=240 ohm X1=0.73 ohm X`2=0.73 ohm Xm=49.2 ohm Secondary Load impedance ZL=0.387+J0.29 solve the exact equivalent circuit with normal voltage across primery.. I know every thing but i cant find CURRENT I1=? and I`2=? Please help me give solution or only Formula please please...
how to calculate cable size in diffrent loads?
Capacitor is load free component but why ampere meter shows current when capacitor bank breaker close?