9*9 1:4:8 ratio using how to calculate the material for
40mm aggregate ,cement &sand please tell me answer
Answer Posted / sravan875
1:4:8 Ratio means 1%cement,4%aggregate,8%sand.
cement percentage--1/13=0.0769231cum.
aggregate %---4*0.0769...=0.3076924cum.
Sand % ----8*0.0169...=0.6153848cum..
Cement=0.0769*2370kg/cum (unit weight of concrete)=182.30775kg
40mm Aggregate=(density 1950kg/cum).
aggregate needed=0.3076924*1950=600.00kg of aggregate
Sand density(dry,packed)---1600-1900kg/cum
sand(dry,packed)-0.6153848*1750=1076.9234 Kg of sand is required.
Cement=182.3 Kgs
Aggregate=600Kgs
Sand=1077 Kgs
| Is This Answer Correct ? | 3 Yes | 18 No |
Post New Answer View All Answers
What is the development length given in pile?
what else we can add rather than admixture in concrete to reduce the cement quantity?
What is the crank length in the slab?
Why M15 is replaced by M20 when ammendment are made in IS456 in 2000?
how can we construct building without foundation providing only grade beam at ground level
Why should appointment store person for project ? what is the benefits for company ?
Describe the role of independent Quantity surveyor?
Steel requirement in kg of 6" thk slab Total qty 32.64 m3 Beam / column qty 35.39 m3
Which Types Of Bricks ?
What is demising walls?
How to find weight of steel in kg if we know the area which is in m2? Following details are known to us, Area=125m² thk of slab=250mm Steel details:T12@200 PS:considering mesh top and bottom with X and Y direction
How will be cutting in timber plate size 600*400 column size
What are your goals?
What do you mean by honeycomb in concrete?
Difference between lime, distemper and plastic emulsion?