Interested to Buy Any Domain ? << Click Here >> for more details...
why java does not support multiple inheritance
- 41 Answers
- 106175 Views
- Diamond, Euclid, Evergent, KLKJ, Mind Tree, NIIT, SSI Small Scale Industries, Wipro, I also Faced
- E-Mail Answers
Answer Posted / professor pandit
Java does not support multiple inheritance of classes.
Answer as to its reasons on why it does not support MI runs
much deeper than what generally seems to be written above.
Java like all OO languages aims to regulate and stream-line
the way in which average developer thinks. It is true that
in real world (from software designer perspective), an
entity, an object does exhibit functions from seemingly
different sets (aka classes).
It is true that implementing multiple inheritance is
difficult at compiler level and complexity is hardly ever
clearly explained in any example. Every single example of
MI that demonstrates its complexity seems contrived and are
generally name-collisions. Assuming that I did seriously
want to inherit class C from both A and B, why on earth
would I give same names to two distinct functions
originating from class A and class B? One could be foo()
and other could be foofoo(); (I hope you get the drift).
C++ designers bent-over-their-back and solved the problem
of MI and even the diamond problem.
Although, Diamond problem is successfully handled by C++,
any sane designer team could have a coding standards that
favour avoidance Diamond inheritance until the die-hard
developer convinces upper crust of its essentials.
Ironically, the major part of Java's decision on "why" of
avoiding MI lies in C++ implementation of it.
While I am grossly simplifying here, Crux of C++ solution
of implementing MI under the hood hinges upon properly
managing the v-table at run-time and unambigious usage of
redundant methods ( in case of diamond) are handled.
In case of Java, design goal was operability across
multiple platforms and industrial strength stability.
Both of these goals can be seriously compromised if MI (and
C++ solution of v-table) were implemented.
Therefore, Java designers choose to let go of a smaller
nice-to-have feature (MI for classes) in favour of Multiple
Platform (essential design goal)
| Is This Answer Correct ? | 0 Yes | 0 No |
Post New Answer View All Answers
What is the synonym of framework?
Is an empty arraylist null?
What is pangram in java?
When should I use stringbuffer?
which pattern is default in scanner package?
What is a singleton class? Give a practical example of its usage.
What is the use of singleton?
Difference between current previous versions of Java?
What is runtime locatable code?
what is deadlock? : Java thread
What is the use of arrays tostring () in java?
Which package is always imported by default?
What is the use of parse function in java?
What does I ++ mean?
Why is a string immutable?
