what is the output of following program ?
void main()
{
int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);
}
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Answer Posted / shenbagam
in c its left to right operation will be perfomed by
compiler..... so take this
int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);
i=5;
--i=4; after tis the value of i=4 only;
because --i will decrement the value of i, and then return the decremented value.
++i=5; after this the value of i=5;
because ++i will increment the value of i, and then return the incremented value.
i--=5; after this the value of i=4;
because will decrement the value of i, but return the pre-defind value of i. so i=5 before the step na?.....
i++=4; after this the value of i=5;
because will increment the value of i, but return the pre-defined value of i.so i=4 before the step na?...
so only the result will be like 45545 this.......
int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);
after the step if u print i; the value must be 5
only......... so the doubt will be cleared aha?............
all the best:):):):).
| Is This Answer Correct ? | 4 Yes | 3 No |
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