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what is the output of following program ?
void main()
{
int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);
}

Answer Posted / shenbagam

in c its left to right operation will be perfomed by
compiler..... so take this

int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);


i=5;

--i=4; after tis the value of i=4 only;

because --i will decrement the value of i, and then return the decremented value.

++i=5; after this the value of i=5;

because ++i will increment the value of i, and then return the incremented value.

i--=5; after this the value of i=4;

because will decrement the value of i, but return the pre-defind value of i. so i=5 before the step na?.....

i++=4; after this the value of i=5;

because will increment the value of i, but return the pre-defined value of i.so i=4 before the step na?...


so only the result will be like 45545 this.......


int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);

after the step if u print i; the value must be 5


only......... so the doubt will be cleared aha?............

all the best:):):):).

Is This Answer Correct ?    4 Yes 3 No



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