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what is the output of following program ?
void main()
{
int i=5;
printf("%d %d %d %d %d ",i++,i--,++i,--i,i);
}
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Answer Posted / sandeep gupta
Friends, actually the output is compiler dependent. Never
give any specific answer in this type of questions because C
does not provide any format in evaluation order of postfix
and prefix expressions when passed to any functions like
printf() eg. fun1(i++,i) may pass fun1(5,6) in some
compilers and fun1(5,5) in another. So it totally depends on
what compiler we're using.
| Is This Answer Correct ? | 4 Yes | 0 No |
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