Answer Posted / prashanth

For Slab-arround 75 kgs/Cum steel will consume.
ie Vol=Mass/Density
=75/7850
= .0095
For one Cum includes (Concrete and Steel)
ie =1-.0095
=.99 (Concrete)
Then ratio=.0095/.99
=.00955 X 100
=.95 (Ratio between concrete and steel)

For Beam-arround 130 kgs/Cum steel will consume.
ie Vol=Mass/Density
=130/7850
= .0165
For one Cum includes (Concrete and Steel)
ie =1-.0165
=.983 (Concrete)
Then ratio=.0165/.983
=.0167 X 100
=1.67 (Ratio between concrete and steel)

For Beam-arround 150 kgs/Cum steel will consume.
ie Vol=Mass/Density
=150/7850
= .0191
For one Cum includes (Concrete and Steel)
ie =1-.0165
=.98 (Concrete)
Then ratio=.0191/.98
=.0194 X 100
=1.94 (Ratio between concrete and steel)

Hi all, please guide me about the volume. And percentage. Of steel fibre to be used. My project. Is Sifcon.

2272

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2138

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