Answer Posted / jack

#include"stdafx.h"
#include<iostream>


using namespace std;
void sort(int[],int );
int maxproduct(int ar[],int n);
int main()
{
int arr[]={2,7,9,5,3,6,-12};

cout<<maxproduct(arr,7);
system("calc");


system("pause");
return 0;
}
void sort(int array1[],int n)
{
for(int i=1;i<n;i++)
for(int r=0;r<n-1;r++)

if(array1[r]>array1[r+1])
{
int temp=array1[r];
array1[r]=array1[r+1];
array1[r+1]=temp;
}

}
int maxproduct(int ar[],int n)
{
sort(ar,n);
int max=1;
for(int i=n-1;i>=n-3;i--)
max*=ar[i];
return max;
}

Teta-Omeg-Big-Oh Show that f(n) = n2 + 3n3 is ;(n3).

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