Answer Posted / g.s.reddy

public class Example {
public static void main(String args[]) throws Exception {
String input = "HAT";
showPattern("", input);
}
public static void showPattern(String st, String chars) {
if (chars.length() <= 1)
System.out.println(st + chars);
else
for (int i = 0; i < chars.length(); i++) {

try {
String newString = chars.substring(0, i)
+ chars.substring(i + 1);
showPattern(st + chars.charAt(i),newString);
} catch (Exception e) {
e.printStackTrace();
}
}
}
}

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Is there any way to find whether software installed in the system is registered by just providing the .exe file? I have tried the following code but its just displaying the directory structure in the registry. Here the code : package com.msi.intaller; import java.util.Iterator; import ca.beq.util.win32.registry.RegistryKey; import ca.beq.util.win32.registry.RootKey; public class RegistryFinder { public static void main(String... args) throws Exception { RegistryKey.initialize(RegistryFinder.class.getResource("jRe gistryKey.dll").getFile()); RegistryKey key = new RegistryKey(RootKey.HKLM, "Software\\ODBC"); for (Iterator subkeys = key.subkeys(); subkeys.hasNext();) { RegistryKey subkey = subkeys.next(); System.out.println(subkey.getName()); // You need to check here if there's anything which matches "Mozilla FireFox". } } }

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