#!/bin/sh select num in 1 2 3 any; do case $num in

Create a bash shell script that reads in a number from the
user. If the number is 1, print out the date. If the number
is 2, list the files in the current directory. If the number
is 3, print out who is currently logged onto the system. If
the number is anything else, print out an error message and
exit. Name this script "various.sh"

Question Posted / prasad

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Answer Posted / prasad

#!/bin/sh

select num in 1 2 3 any; do
case $num in
1) date;;
2) ls;;
3) who;;
*) echo "Error"; break;;
esac
done

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