If a fixed gear having 200 teeth is in mesh with another
gear having 50 teeth.The two gear are connected by an
arm.What will be the number of turn made by the smaller gear
for one revolution of arm about the center of bigger gear?
Any effort is appreciable witha proper logic..
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Answer Posted / prajapati piyush p.
its a problem of epicyclic gear train.
let A=turn of bigger gear,B=turn of smaller gear,C=arm which is fixed.
turn of bigger gear relative to arm=A-C
turn of smaller gear to arm=B-C
since smaller and bigger gear rotates in opposite direction,
B-C/A-C= (-)teeth on bigger gear/teeth on smaller gear
since bigger gear is fixed A=0,
B-1/0-1=(-)200/20,
B=21.ans
smaller gear will turn 21 turns.
| Is This Answer Correct ? | 3 Yes | 19 No |
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