Answer Posted / manish
corona loss p
= .00241[(f+25)/$]*[root of (r/d)]*square of[Vp-Vo]
f= supply frequency
$= air density correction factor
Vp = operating voltage
Vo= critical disprutive voltage
r= radius of conductor
d= distance of separation for fine weather
now for dc f=0 then a certain power loss by corona but less then ac corona loss.
| Is This Answer Correct ? | 8 Yes | 2 No |
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