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main()
{
int a=5;
printf(?%d,%d,%d\n?,a,a< <2,a>>2);
}
Answer: 5,20,1 please explain this code in detail
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Answer Posted / saikumar
main()
{
int a=5;
printf("%d,%d,%d\n",a,a<<5,a>>2);
}
explanation:in the above program already we assinged a value is 5.
in the printf statement a is 5
and a<<2 it means 'a' leftshift 2 it should converted in to binary form .first we take 5 is in the binary form is 101.
and next we take 2 is in the binary form 010.
we have to shift the 5 to left side of 2 terms .
101<<010=10100=20.
101>>010=001=1.
output:
5
20
1
| Is This Answer Correct ? | 0 Yes | 0 No |
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