Answer Posted / addu
#include<stdio.h>
double pow(int,int);
main()
{
int m,n;
double res;
printf("Enter the number and the power : ");
scanf("%d%d",&m,&n);
res=pow(m,n);
printf("\nThe result is = %d\n",res);
}
pow(int m,int n)
{
if(n>0)
{
return m* pow(m,n-1);
} else if (n==0){
return 1;
} else {
return (1/((double)m))*pow(m,n+1);
)
}
| Is This Answer Correct ? | 5 Yes | 2 No |
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