Answer Posted / ubaid

Copy and paste it will run successfully..
#include<conio.h>
#include<stdio.h>
void Ubaid(int x)
{
for(int i=x;i>0;i--)
{
printf("\n");
for(int j=1; j<=i; j++)
{
printf("%d",j);
}
for(int u=i-1;u>0;u--)
{
printf("%d",u);
}
}
//start another from here
for(int p=1;p<=x;p++)
{
printf("\n");
for(int e=1;e<p;e++)
{
printf("%d",e);
}
for(int o=e;o>0;o--)
{
printf("%d",o);
}
}

}
void main()
{
clrscr();
printf("the output of function is..");
printf("\n");
printf("\n");
Ubaid(6);
getch();
}

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