. There are two water tanks A and B, A is much smaller than
B. While water fills at the rate of 1 liter every hour in
A, it gets filled up like, 10, 20, 40,80, 160…..in tank B.
(At the end of first hour, B has 10 liters, second hour it
has 20 liters and so on). If tank B is 1/32 filled of the
21 hours, what is total duration of hours required to fill
it completely?
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Answer Posted / sri
10+20+40+80+160
10(1+2+4+8+16)
this is a gp
first term=a
ratio=2
t21=1*2^20
x=2^25
therefore in gp
tn=ar^n-1
n-1=25
n=26
26 hrs
| Is This Answer Correct ? | 15 Yes | 2 No |
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