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Explain this code.
#include <stdio.h>
void f1(int *k)
{
*k = *k + 10;
}
main ( ){
int i;
i = 0;
printf (" The value of i before call %d \n", i);
f1 (&i);
printf (" The value of i after call %d \n", i);
}
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Answer Posted / vivek
it will produce an error as constant cant be added to a pointer
| Is This Answer Correct ? | 1 Yes | 4 No |
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