what is the conversion factor for nm3 to kg/hr in air flow
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Answer Posted / hermann
1Nm3 (normal m3) of air is a volume of 1m3 of air under
normal conditions of pressure (1 atm = 101.330 kPa) and
temperature (0 deg C = 273 K) (Europe);
Since air can be assumed to behave as an ideal gas under
those conditions, its compressibility factor is 1; so in
the relation:PV=ZmRT; Z=1;R for air= 0.287 kPa.m3/(kg.K);
V=1m3; therefore 101.330*1=1*m*0.287*273; so m = 1.295 kg.
Conversion factor: 1 Nm3/hr = 1.295 kg/hr
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A PLC is programmed to drive three motors A, B and C as follows : After running motor A for an hour, motor B should get ON and motor A should get OFF. And after running motor B for an hour, motor C should get ON and motor B should get OFF. And after running motor C for an hour, motor A should get ON and motor C should get OFF. (That is, a cyclic repetition with time period one hour) Now, the second condition is: If any motor gone faulty and is tripped, the consecutive motor should get ON and the faulty (tripped) motor should be eliminated from cyclic repetition. The remaining two motors should bear the cyclic repetition of one hour each. (For healthy motor take logic as high and for tripped motor take logic as low) Now, the third condition is: When motor A load(Amps) exceeds 60% of its rated load, motor B should get ON in parallel to motor A. And when both motors A & B are running in parallel, and if their load exceeds 60% of their rated load, motor C should also start in parallel to A & B. [Here the cyclic repetition is eliminated, until their loads become normal(40%)] [Take logic high(1) for load at 60% and logic low(0) for load at 40%] Now draw a flow chart or a ladder diagram to fulfill the above condition.
