Answer Posted / shiva

No.
in g++ you will be clearly notified that you can't define a
function inside another function
but gcc somehow allows following

#include <stdio.h>

int func2(int (*f)()){
(*f)();
return 0;
}
int main ()
{
int func1 ()
{
printf ("\n Inside func 1 ");
return 0;
}
printf("someting");
func1 (); //you can access this fuction inside
main(the function in which you declared func1) with the name
func1
func2(func1); // to access this function outside use
fucntion pointer as a argument
return 0;
}

o/p:
something
Inside func 1
Inside func 1

Tell me when is a void pointer used?

1102

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