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what will be the output of this program?
#include<stdio.h>
#define cube(x) x*x*x
void main()
{
int i,j=5;
i=cube(j+3);
printf("i=%d",i);
}
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Answer Posted / sunil samal
38 because above declared the pree processer directive # defind cube (x) x*x*x
it passes the value (5+3)to the above directive
So the operation will be as
5+3*5+3*5+3
Hence
5+15+15+3=38
| Is This Answer Correct ? | 5 Yes | 1 No |
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