Answer Posted / guest

void main()
{
int n,a,b;
sanf("%d%d",&a,&b);
printf("select one of these");
printf("1.addition
2.subtraction
3.multiplication
4.division");
scanf("%d",&n);
if(n==1)
{
printf("%d",a+b);
}
else if(n==2)
{
printf("%d",a-b);
}
else if(n==3)
{
printf("%d",a*b);
}
else if(n==4)
{
printf("%d",a/b);
}
else
{
printf("nothing to print");
}
}

Write a client and server program in C language using UDP, where client program interact with the Server as given below: i) The client begins by sending a request to send a string of 8 characters or series of 7 numbers, the server sends back a characters or numbers as per the request of the client. ii) In case of series of 7 numbers: The client sends a multiplication of numbers, to the server. iii) In case of a string of 8 characters: The client sends a reverse order of string to the server.. iv) Server will send an acknowledgment to the client after receiving the correct answer

4305

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You have given 2 array. You need to find whether they will create the same BST or not. For example: Array1:10 5 20 15 30 Array2:10 20 15 30 5 Result: True Array1:10 5 20 15 30 Array2:10 15 20 30 5 Result: False One Approach is Pretty Clear by creating BST O(nlogn) then checking two tree for identical O(N) overall O(nlogn) ..we need there exist O(N) Time & O(1) Space also without extra space .Algorithm ?? DevoCoder guest Posted 3 months ago # #define true 1 #define false 0 int check(int a1[],int a2[],int n1,int n2) { int i; //n1 size of array a1[] and n2 size of a2[] if(n1!=n2) return false; //n1 and n2 must be same for(i=0;ia1[i+1]) && (a2[i]>a2[i+1]) ) ) return false; } return true;//assumed that each array doesn't contain duplicate elements in themshelves }

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