Interested to Buy Any Domain ? << Click Here >> for more details...
100V supply is appllied between 500K Resistance bulb. for 1
kwh energy, how long time the bulb will glow? explain the
calculating method.
- 3 Answers
- 6126 Views
- Bhel, I also Faced
- E-Mail Answers
Answer Posted / manish
POWER P = V * I = V * V/R = 100 * 100/(500*1000)
= 10000/500000 = 1/50 = 0.02 WATTS
GIVEN ENERGY = 1 KWH = 1000 WATT HOUR
TIME FOR WHICH BULB WILL GLOW
= (1000 WATT HOUR) / (0.02 WATT)
= 1000/0.02 HOURS
= 50000 HOURS
| Is This Answer Correct ? | 14 Yes | 2 No |
Post New Answer View All Answers
what can be the causes of capacitor start motor having a higher current that its actual
what is two point starter?
what is the responsibility of C license holder in industry?
what is the use of expulsition protective gap in 11Kv line.
write a c++ code that receives an integer number and display the sum of the number and its revers integer?
Vaccum circuit breaker
How to select a contactor? How many types of contactors are available
When and where resistance earthing is used ? How to calculate the time constant for earth fault
what is the difference between RMS & TRUE RMS VOLTAGE
witch pump used in wtp
What is the minimum value of hfe for the oscillations in transistorized rc phase shift oscillator?
solar inverters was not connected to the nuteral link .this nutwral possible to any other systems
State and define norton’s theorem?
How would you relate your key competencies to this position?
why in an industry; machine having rated 200 h.p stopped after power factor is maintained above 0.97 lag by control panel in view-of energy saving
