Answer Posted / rohit

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c,root;
float x1,x2;
printf("enter the roots a,b,c");
scanf("%d %d %d",&a,&b,&c);
if(a=0&&b=0)
printf("no solution");
else
if(a=0)
{
root=-c/b;
printf("root=%d",root);
}
else
if[(b*b-4*a*c)>0]
{
x1=[-b+sqrt (b*b-4*a*c)]/(2*a);
x2=[-b-sqrt (b*b-4*a*c)]/(2*a);
printf("the roots are x1=%f,x2=%f",x1,x2);
}
else
printf("it has imaginary roots");
getch();
}

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