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Sir,please help me out with the output of this programme:-
#include<stdio.h>
#include<conio.h>
void main()
{
int a=18,b=12,i;
for(i=a<b?a:b;a%i||b%i;i--);
printf("%d %d",i);
}
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Answer Posted / manish soni bca 3rd year jaipu
hi frds,manis soni tagore collage jaipur
in this prm,
initily
for(i=12;a%i||b%i;i--);
--------|-------|--------|
a%i | b%i | i--;|
--------|-------|--------|
18%12=6*|** |12--=11;|
--------|-------|--------|
18%11=7*|** |11--=10;|
--------|-------|--------|
18%10=8*|** |10--=9; |
--------|-------|--------|
18%9=0 *|12%9=3 |9--=8; |
--------|-------|--------|
18%8=2 *|** |8--=7; |
--------|-------|--------|
18%7=4* |** |7--=6; |
--------|-------|--------|
18%6=0 *|12%6=0 |***; |
--------|-------|--------|
summory of the program
here we dissuss sum property
-----------------------------------
coition1||(or operaor)conditon 2;
-----------------------------------
in this case if condition1 is ture then
the second condition will not excute;
this is property of OR opr.
------------------------------------
here->(*)is represent condition1 and
------------------------------------
2.if c1 is false then c2 is true
this is represent **.
--------------------------------------
if c1 and c2 both are false then
***.
this is termination point.
and print 6;
bcoz at 6 both the condition are false.
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